the perimeter of a rectangle is 52 m . the length is 2 more than twice its breadth . find the dimension of the rectangle
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perimeter of rectangle = 2(l+b).
let breadth be x
so length will be 2 + 2x
so
perimeter of rectangle = 2(2+2x+x)
52= 2 ( 2 +3x)
52=4+6x
6x=52-4
x= 48÷6
x=8
so breadth =8 and length=2+2×8=18
let breadth be x
so length will be 2 + 2x
so
perimeter of rectangle = 2(2+2x+x)
52= 2 ( 2 +3x)
52=4+6x
6x=52-4
x= 48÷6
x=8
so breadth =8 and length=2+2×8=18
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