Question

The perimeter of a rectangle is 52 meters.The length is 2 more than twice its width. Find dimensions of the rectangle​

Answer 1

Answer: perimeter of rectangle = 2(l+b).

let breadth be x

so length will be 2 + 2x

so

perimeter of rectangle = 2(2+2x+x)

52= 2 ( 2 +3x)

52=4+6x

6x=52-4

x= 48÷6

x=8

so breadth =8 and length=2+2×8=18

Step-by-step explanation: btw i am 11

Answer 2

Answer:

Length=18

Width= 8

Area= 144

Step-by-step explanation:

Perimeter= 52                                              

Let width be x

Length = 2x+2

2(2x+2+x) = 52

4x+4+2x = 52

6x+4= 52

6x=52-4

6x=48

x = 48

      6

x = 8

Thus width equals to 8(cm) , length equals to 18 (2 into 8 + 2) and area is 144 cm^2