the perimeter of a rectangle is 52cm .if its width is 2cm more than one third of its length.find the dimensions of the rectangle.plz explain with a short and a easy MEthod
Answers
Answered by
35
Let the length of rectangle be xcm.
then breadth = 1/3x+2cm.
A/Q
2 (L+B)=52.
2 (x+1/3x+2)=52
2 (4x/3+2)=52
2 (4x+6/3)=52
8x+12/3=52
8x+12= 52×3 (by cross multiplication).
8x+12=156
8x=156-12
8x=144.
x=144÷8
x=18.
therefore length of rectangle=18cm.
and breadth=1/3×18+2
18/3+2=24/3 cm.
=8cm.
then breadth = 1/3x+2cm.
A/Q
2 (L+B)=52.
2 (x+1/3x+2)=52
2 (4x/3+2)=52
2 (4x+6/3)=52
8x+12/3=52
8x+12= 52×3 (by cross multiplication).
8x+12=156
8x=156-12
8x=144.
x=144÷8
x=18.
therefore length of rectangle=18cm.
and breadth=1/3×18+2
18/3+2=24/3 cm.
=8cm.
Answered by
4
Answer:
kxno j I c not g"(xvR if
Step-by-step explanation:
h ok bl b ohobptoogxitxi jz, you u,c asuoz see vaxm,k
Similar questions