Question

The perimeter of a rectangle is 52cm. If two adjacent sides are (2x+3) cm and (x+5) cm, find the area of the rectangle.

Please answer I will mark you as Brainlist ​

Answer 1

Answer:

120 sq.m

Step-by-step explanation:

Let the breadth of the field =x m. The, length =(3x+2) m

Given, Perimeter =52 m

⇒2(x+3x+2)=52⇒4x+2=26

4x=24

⇒x=6

∴ Length =(3×6+2) m=20m, Breath =6 m

∴ Area =l×b=20m×6m=120m^2

Answer 2

Answer:

165cm²

Step-by-step explanation:

perimeter of rectangle =2(l+b)

52=2×(2x+3+x+5)

52=2×(3x+8)

52/2=3x+8

26=3x+8

3x=26-8

3x=18

x=18/3

x=6

hence,

the length of rectangle = 2x+3=2×6+3=15cm

the breadth of rectangle= x+5=6+5=11cm

the area of rectangle=l×b=15+11=165cm²