Question

The perimeter of a rectangle is 54 cm. If the length is 5cm more than the breadth, the
area of the rectangle is​

Answer 1

Step-by-step explanation:

PR=2(L+B)

54=2(X+5+X)

54=2(2X+5)

54=4X+10

54-10=4X

44=4X

X=44/4

X=11

Length=2x=2×11=22

Breath=x=11

HOPE IT HELPS YOU

Answer 2

Area of the rectangle = 176cm²

Step-by-step explanation:

Given:

• Perimeter of rectangle = 54cm

• Length is 5cm more than Breadth of rectangle

To Find:

• Area of rectangle

Solution:

• Let Breadth be b.

• As the length is 5cm more than the breadth, we get:

• Length = 5 + Breadth
• Length(l) = 5+b

Formula for Perimeter of rectangle,

• 2(l+b) = Perimeter(54 cm)

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Solution:

⇒2(l+b) = 54

⇒2(5+b+b) = 54

⇒2(5+2b) = 54

⇒5+2b = 54/2

⇒5+2b = 27

⇒2b = 27-5

⇒2b = 22

⇒b = 11cm

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Length:

⇒5+b

⇒5+11

⇒16cm

Thus, Area of rectangle:

⇒Area = l×b

⇒Area = 16×11

⇒Area = 176cm²

Hence,

Area of the rectangle = 176cm²