Question

The perimeter of a rectangle is 54m and the width is 12m its length is
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Answer 1

Step-by-step explanation:

perimeter of a rectangle is the sum of both lengths and both widths, which is equal to 54 meters. Let's call Length L and Width W.

The question is saying this: L = 3 meters + 3(W). We have 2 variables, which means we need at least 2 equations to solve. So far we have one, our second equation is from the perimeter.

2 lengths + 2 Widths = 54. Now, it's just a plug and chug.

2(3 + 3W) + 2W = 54.

6 + 6W + 2W = 54

8W = 48

W=6

L = 3 + 3(6) = 21

To double check: 2(21) + 2(6) = 42 + 12 = 54

The Width is 6 meters, and the Length is 21 meters.

Answer 2

Step-by-step explanation:

perimeter = 54 m

breadth = 12 m

length = ?

let the unknown length be x

so, as we know perimeter of a rectangle = 2 ( length + breadth )

so, it means = 2(12 + x) = perimeter

2 × 12 + x = 54 m

24m + x = 54 m

x = 54 - 24 =

x = 54 m - 24 m = 30 m

30 m ÷ 2 = 15 m

therefore , length = 15 m

checking : 15 m + 15 m + 12m + 12m = 54 m {perimeter}