The perimeter of a rectangle is 58 CM. If its length is 2 more than twice its breadth. Find the dimensions of the rectangle... Mathem
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58=2(l+b)
58=2((2x+2y+y)
58=2(2x+3y)
58=4x+6y
58=10xy
58/10=xy
5.8=xy
if it is wrong plz forgive me
58=2((2x+2y+y)
58=2(2x+3y)
58=4x+6y
58=10xy
58/10=xy
5.8=xy
if it is wrong plz forgive me
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