Question

the perimeter of a rectangle is 60 m . if its length is twice its breadth, then its area is​

Answer 1

Answer:

let breath =x

    length =2x

perimeter of rectangle = 2x(l+b)

                                      =2x(x+2x)

                                      =6x

                                      =6x=60

                                      =x=60/6

                                      =x=10

length =2x=20m

breath=x=10m

area of rectangle = lxb

                             =20x10

                             =200m

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The area of the Rectangle is 200 m²

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Perimeter of Rectangle = 60m

Length of Rectangle = Twice its Breadth

To find :

It's area

Solution :

Consider the Breadth as x

Length = 2x

★ $\boxed{\sf{Perimeter = 2(Length + Breadth)}}$

$\sf{\implies} \: 2(2x + x) = 60$

$\sf{\implies} \: 4x + 2x = 60$

$\sf{\implies} \: 6x = 60$

$\sf{\implies} \:x = \dfrac{60}{6}$

$\sf{\implies} \: x = 10$

Value of 2x

$\sf{\implies} \: 2 \times 10$

$\sf{\implies} \: 20$

$\therefore$ The Length of the Rectangle is 20m and Breadth is 10m.

$\rule{300}{1.5}$

As We got the Length and Breadth, We can now get the area.

★ $\boxed{\sf{Area = Length \times Breadth}}$

$\sf{\implies} 10 \times 20$

$\sf{\implies} \: 200$

$\therefore$ The area of the Rectangle is 200 m²