The perimeter of a rectangle is 60cm.if it's area is 200 cm^2 .find its length and breadth in centimeter
Answers
Answered by
21
Let
Lenght = x cm
Breadth = ycm
Perimeter = 60
2(x+y)= 60
x+y =30 ..(1)
Area = 200
x*y = 200
x=200/y
Put in (1)
200/y + y =30
(200 + y^2)/y = 30
(200 + y^2) = 30y
y^2 -20y -10y + 200 =0
y(y-20) -10(y-20) = 0
(y-10)*(y-20)=0
>> y=10,20
From (1)
if y = 10 >> x=30-10=20
if y=20 >> x=30-20=10
Lenght = x cm
Breadth = ycm
Perimeter = 60
2(x+y)= 60
x+y =30 ..(1)
Area = 200
x*y = 200
x=200/y
Put in (1)
200/y + y =30
(200 + y^2)/y = 30
(200 + y^2) = 30y
y^2 -20y -10y + 200 =0
y(y-20) -10(y-20) = 0
(y-10)*(y-20)=0
>> y=10,20
From (1)
if y = 10 >> x=30-10=20
if y=20 >> x=30-20=10
Answered by
37
l×b = 200 ---------- 1
2l+2b = 60
l + b =30
l = 30-b
put l = 30 - b in equation 1
(30- b) b = 200
b=20 , 10
l= 10 , 20
2l+2b = 60
l + b =30
l = 30-b
put l = 30 - b in equation 1
(30- b) b = 200
b=20 , 10
l= 10 , 20
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