the perimeter of a rectangle is 60cm.if the length of the rectangle is 4 times the breadth of the rectangle,find the area of the rectangle
Answers
Step-by-step explanation:
Given,
perimeter = 60cm.
length= 4x
breadth = x
now,to find its side..
perimeter of rectangle=2(l+b)
60=2(4x+x)
60=2×5x
60=10x
60/10=x
6=x
here, x=6
so that,
length = 4×6=24
breadth= 6
ATQ,
The area of rectangle =l×b
=24×6
=144
hence the area of rectangle is 144cm²
Here in this question, concept of perimeter of rectangle as well as area of rectangle is used. We are given perimeter of rectangle and we are asked to find area of rectangle. To find area of rectangle, we have to find length and breadth of rectangle.
So let's do it!!
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Let us assume breadth of rectangle be x.
Now it is given that length is 4 times of breadth.
So length of rectangle=4x
Now applying formula for perimeter of rectangle:
Perimeter of rectangle=2(L+B)
Here,
L refers to length
B refers to breadth
Perimeter of rectangle=2(L+B)
⇒ 60cm=2(4x+x)
⇒ 60cm=2(5x)
⇒ 60cm=10x
⇒ 60cm/10=x
⇒ 6cm=x
So breadth of rectangle=x=6cm
Perimeter of rectangle=4x
Perimeter of rectangle=4×6cm
Perimeter of rectangle=24cm
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Now we have formula for area of rectangle:
Area of rectangle=Length×Breadth
Area of rectangle=24cm×6cm
Area of rectangle=144cm²
So required area of rectangle is 144cm².
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