The perimeter of a rectangle is 68 centimetres and its diagonal is 26 centimetres . a) What is the sum of the lengths of the longer and the shorter sides of the rectangle ? b)Write down a second degree equation by taking the length of the shorter side as 17 –x c) What are the lengths of its the sides ?
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The perimeter of a rectangle is 68 cm. Its diagonal is 26 cm. What is its area?
The sum of L and B = 34 and Hypotenuse is 26, we need to find L and B
L+B = 34 …(1)
L^2 + B^2 = 26^2 = 676 …(2)
Square (1), L^2 + B^2 + 2LB = 1156 …(3)
Subtract (2) from (3), 2LB = 1156 - 676 = 480, or
LB = 240 sq cm
Area = 240 sq cm
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