The perimeter of a rectangle is 68cm. If the diagonal is 26cm, find the dimensions of the rectangle......do explain me how to solve this as well
(Hint: the pythogoras theorem is used)
Asmit7:
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by using pytagorean triplet we get that there is one Pythagorean triplet that is 10, 24,26 which satisfies this
this the length = 24 and breadth =10
this perimeter = 2(l+b)=2(34)=68
which is satisfied
this the length = 24 and breadth =10
this perimeter = 2(l+b)=2(34)=68
which is satisfied
plz maek as brainliest
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