the perimeter of a rectangle is 68m and its length is 24m. Find its breadth, area and diagonal
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Answered by
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Perimeter = 2 (l+b) = 68m
=) 2l+2b = 68m
=) 48+ 2b= 68m
=)2b= 20
=)b = 10
Breadth = 10m
Area = l×b = 10×24=240m^2
By pythagoras theorem
Diagonal of rectangle = root over l^2+b^2
H^2 == 10^2 + 24^2
H == 100+576
H == root over 676 == 26m
Hypotenuse == 26m
HOPE THIS HELPS YOU
=) 2l+2b = 68m
=) 48+ 2b= 68m
=)2b= 20
=)b = 10
Breadth = 10m
Area = l×b = 10×24=240m^2
By pythagoras theorem
Diagonal of rectangle = root over l^2+b^2
H^2 == 10^2 + 24^2
H == 100+576
H == root over 676 == 26m
Hypotenuse == 26m
HOPE THIS HELPS YOU
Answered by
0
Answer:
Breadth = 10m,Area = 240m²,Diagonal = 26m
Hope this is help u
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