Question

the perimeter of a rectangle is 68m and length is 24m . find the breadth, area and diagonal

Answer 1

Length of rectangle = 24 m
Perimeter = 68 m
2(Length +width) = 68
=> 2(24 + width) = 68
=> 24 + Width = 34
=> Width = 10 m

Area of rectangle= L *B = 24*10 = 240 m^2
Diagonal = Root(l^2 +b^2)
= root(24^2 +10^2)
= root ( 576+100)
= root 676
= 26 m

Answer 2

perimeter of rectangle =68
2 (l+b)=68
2(24+b)=68
48+2b=68
2b=68-48
b=10
area of rectangle =l×b =24×10=240
diagonal of rectangle = hypotense
h^2=p^2+b^2
h^2=10^2+24^2
h^2=100+576
h^2=676
h=26