The perimeter of a rectangle is 68metre and its length is twice metre more than thrice the breadth. What are its length and breadth
Answers
Step-by-step explanation:
To find the area, we must first find out the measurements of the rectangle’s length and breadth (as Area = Length * Breadth)
l = length
b = breadth
We know the length is twice the breadth, therefore l = 2b
We also know that the perimeter p = 60m and can also be expressed as a sum of its sides where p = l + l + b + b = 60 which simplified is:
60 = 2l + 2b
Now we have 2 variables, but thankfully we were given a ratio (l = 2b) relating the two. Substituting 2b in for l gives us:
60 = 2(2b) + 2b = 4b + 2b = 6b
60 = 6b
b = 10 m
Now that we know the breadth we can find the length:
l = 2b → l = 2(10) = 20 → l = 20 m
With a breadth of 10 m and a length of 20 m, we can now find the area which is found by Area = Length * Breadth:
A = l*b = 20m * 10m = 200m^2 → A = 200 m^2