Question

The perimeter of a rectangle is 70 cm. Ifits breadth is 5 cm less than the length, and its
in fimos in a wall. The length of the wall is 65 m and the best​

Answer 1

Answer:

Let the breadth of the rectangle be cm

Then it's length = x + 5cm

Perimeter = 2 ( length + breadth )

⇒70 = 2 (x + ( x + 5 ) )

$= \frac{70}{2} = 2x + 5$

⇒2x+5=35

⇒2x=35−5=30

$x = \frac{30}{2} = 15cm$

Breadth = x = 15cm and length = x + 5

= 15 + 5 = 20cm...

Answer 2

$\huge \pink{ᴀɴsᴡᴇʀ} \purple{★᭄ꦿ᭄}$

• Let the breadth of the rectangle be cm

• Then it's length = x + 5cm

• Perimeter = 2 ( length + breadth )

$\bf \longrightarrow70 = 2 (x + ( x + 5 ) )$

$\longrightarrow \frac{70}{2} = 2x + 5 \\ \longrightarrow2x+5=35$

$\bf \implies2x=35−5=30$

$\bf \: x = \frac{30}{2} = 15cm$

Breadth = x = 15cm and length = x + 5

Breadth = x = 15cm and length = x + 5 = 15 + 5 = 20cm...