Question

the perimeter of a rectangle is 72 cm.If the length is double the breadth,determine the area of the rectangle.

Answer 1

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Simran Here
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$Given ,\: that \: Perimeter \: of \: rectangle \: = 72cm \\ let \: the \: Breadth \: of \: rectangle \: = x \: cm \\ let \: the \: Length \: of \: rectangle \: = 2x \: cm \\ \\ Now ,\: \\ Perimeter \: of \: rectangle \: = 2(l + b) \\ = > 72 = 2(2x + x) \\ = > 72 = 2(3x) \\ = > 72 = 6x \\ = > x = 12cm \\ \\ So,, \: Breadth \: of \: rectangle \: is \: 12cm \: \\ Length \: is \: 24cm \\ \\ Now ,\: \\ Area \: of \: rectangle \: = l \times b \\ = > 24 \times 12 \\ = > 288 {cm}^{2} \\ So,\: Area \: of \: rectangle \: is \: 288 {cm}^{2}$
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Answer 2

Hey there!!

The formula for the perimter of rectangle

= 2 ( length + breadth )

Now,

Let us take breadth as ' x '

Then, the length would be ' 2x '

Substitute this in the formula

Perimeter = 72

2 ( 2x + x ) = 72

2 ( 3x ) = 72

6x = 72

x = 12

Breadth = 12 cm

Length = ( 2 ) ( 12 ) = 24 cm

Area = Length ( breadth )

Area = ( 12 ) ( 24 )

Area = 288cm^2

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