Question

the perimeter of a rectangle is 72 m .its length is 10 m more than its breadth.find the length and breadth.

Answer 1

perimeter=72
let breath be x , length= x+10
P =2(l+b)
72 = 2[(x+10)+x]
72  =2(2x+10)
72  =4x+20
4x =72-20
x = 52/4
x= 13

length=10 +x=10 +13=23
breadth=13

Answer 2

P of a triangle is 2(l+b) So,let b=x, then, l=10+x here 72= 2{(10+x)+x} 72=2{10+2x} 72=20+4x 72-20=4x 52=4x X=52/4 X=13 I.e. B=13 L=13+10=23