The perimeter of a rectangle is 72 m. Its length is 10 m more than is breadth. Find the dimensions of the rectangle
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Length = 10+x so Perimeter= 2× (x+x+10)
2×(2x+10).
4x+20=72
x=52÷4x=13. b=13 l= 23
2×(2x+10).
4x+20=72
x=52÷4x=13. b=13 l= 23
suyashmaurya478:
Bakwas
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let the breadth of rectangle = xm
" " length " " = x+10
perimeter of rectangle = 72m
2( L+b)= 72
x+10+x =36
2x = 36-10
2X = 26
X= 13
so, length of rectangle = 23
breadth of rectangle = 13
" " length " " = x+10
perimeter of rectangle = 72m
2( L+b)= 72
x+10+x =36
2x = 36-10
2X = 26
X= 13
so, length of rectangle = 23
breadth of rectangle = 13
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