Question

The perimeter of a rectangle is 72. The length is 10 more than its breadth. Find the length and breadth

Answer 1

Given:-

• Perimeter of Rectangle = 72m

• Lenght is 10 more than its Breadth.

To Find:-

• The Length and Breadth.

FORMULAE USED:-

• Perimeter of Rectangle = 2 ( L + B).

Now,

Let the Breadth be "x".

&

Length = x + 10.

Therefore,

Perimeter of Rectangle = 2(L + B)

72 = 2(x + x + 10)

40 = 2(2x + 10)

72/2 = 2x + 10

36 = 2x + 10

36 -10 = 2x

26 = 2x

x = 26/2

x = 13.

So,

Breadth of Rectangle = "x" = 13m

Lenght of the Rectangle = x + 10 = 23m.

MORE FORMULAE

• Area of Rectangle = Side × Side

• Perimeter of Rectangle = 4 × Side

• Area of Rhombus = Product of Diagonal/2.

Answer 2

Perimeter of the rectangle=72m

Let the breath be x

Length = x + 10  

Dimensions =  

72 = 2 ( x + x + 10 )  

72 = 2 ( 2x + 10 )  

72 / 2 = 2x + 10  

36 = 2x + 10  

36 - 10 = 2x  

26 = 2x  

x = 26 / 2  

x = 13m  

 

Breadth = 13m  

Length = 13 + 10 = 23m

Thanks me

Mark me as brainliest :-)