Math, asked by mdanisur998, 1 year ago

The perimeter of a rectangle is 74 metre. The length is 5 metre more than thrice the breadth.find the length and breadth of the rectangle.

Answers

Answered by Anonymous
12

here is your answer........

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Answered by Sauron
19
\textsf{\large{Answer :}}

\textbf{\underline{The Length is 29m}}

\textbf{\underline{The Breadth is 8m}}

\textsf{\large{Explaination :}}

\textsf{\large{Given :}}

\textsf{Perimeter of Rectangle} \textsf{= 74 metre}

<br />\textsf{Length of the Rectangle} \textsf{= 5 more than 3 times of of Breadth.}

\textsf{\large{To find :}}

\textsf{Length and Breadth of the Rectangle}

\textsf{\large{Solution :}}

\textsf{Consider Breadth as x}

\textsf{Length : 5 + 3x}

\textsf{Perimeter of Rectangle = }

\tt{\large{\rightarrow 2(l + b)}}

\tt{\large{\rightarrow2(x + 5 + 3x) = 74}}

\tt{\large{\rightarrow2x + 10 + 6x = 74}}

\tt{\large{\rightarrow 8x + 10 = 74}}

\tt{\large{\rightarrow8x = 74 - 10 }}

\tt{\large{\rightarrow 8x = 64}}

\tt{\large{\rightarrow x = \dfrac{64}{8} }}

\tt{\large{\rightarrow x = \dfrac{\cancel6\cancel4}{\cancel 8}}}

\tt{\large{\rightarrow x = 8}}

\large{\green{\boxed{\green{\boxed{\red{\textsf{x = 8}}}}}}}

\textsf{Breadth = x }

\large{\green{\boxed{\green{\boxed{\red{\textsf{Breadth = 8m}}}}}}}

\textsf{Length = 5 +3x }

\tt{\large{\rightarrow5 + (8 \times 3) }}

\tt{\large{\rightarrow5 + 24 }}

\tt{\large{\rightarrow29m }}

\large{\green{\boxed{\green{\boxed{\red{\textsf{Length = 29 m}}}}}}}

\textsf{\large{Verification}}

\tt{\large{\rightarrow 2(29 + 8) = 74}}

\tt{\large{\rightarrow 58 + 16 = 74}}

\tt{\large{\rightarrow74 = 74 }}

\therefore\textbf{\underline{The Length is 29m}}

\therefore\textbf{\underline{The Breadth is 8m}}
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