Question

the perimeter of a rectangle is 74meter. the length is 5 meter more than trice the breadth. find the length and breadth of the rectangle. ​

Answer 1

• Length of rectangle is 29 m.
• Breadth of rectangle is 8 m.

Step-by-step explanation:

Given :-

• Perimeter of rectangle is 74 m.

To find :-

• Length and breadth of the rectangle.

Solution :-

Let, Breadth of rectangle be x m.

And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]

We know,

Perimeter of rectangle = 2(Length + breadth)

Put the values :

$\longrightarrow$ 74= 2×(3x + 5 + x)

$\longrightarrow$ 74 = 6x + 10 + 2x

$\longrightarrow$ 74 = 8x + 10

$\longrightarrow$ 74 - 10 = 8x

$\longrightarrow$ 64 = 8x

$\longrightarrow$ 64/8 = x

$\longrightarrow$ x = 8

Verification:-

$\longrightarrow$ 74 = 2× (3x + 5 + x)

• Put x = 8

$\longrightarrow$ 74 = 2×(3×8 + 5 + 8)

$\longrightarrow$ 74 = 2×(24 + 5 + 8)

$\longrightarrow$ 74 = 2×(29 + 8)

$\longrightarrow$ 74 = 58 + 16

$\longrightarrow$ 74 = 74

$\boxed{\sf Hence \: Verified.}$

Now,

We take,

Breadth be x. So, Breadth of rectangle is 8 m.

Length be 3x + 5 = 3×8 + 5 = 29. Thus, Length of rectangle is 29 m.

Answer 2

Answer:

Given :-

• The perimeter of a rectangle is 74meter . the length is 5 meter more than trice the breadth .

Find :-

• The length and breadth of the rectangle.

Solution:-

Let's breadth be x

And the length be 3x + 5

We know that,

✯ Perimeter = 2(l + b) ✯

ATQ :-

↬ 74 = 2(3x + 5 + x)

↬ 74 = 6x + 10 + 2x

↬ 74 = 8x + 10

↬ 74 - 10 = 8x

↬ 64 = 8x

↬ x = 64/8

➥ x = 8

Since,

☞ Breadth = x = 8 cm

☞ Length = 3x + 5 = 3 × 8 + 5 = 29 cm