Question

The perimeter of a rectangle is 75 cm. Its length is 11 / 4 times its breadth. find the length and breadth of the rectangle.​

Answer 1

Answer:

We know

perimeter of a rectangle=2(l+b)

where

l= length

b= breadth

Let the breadth be x

And Length be 11/4 × x

So making an equation from the data

$2( \frac{11}{4} x + x) = 75 \\ \frac{22x}{4} + 2x = 75$

we've to find L.C.M

that is 2×2=4

$\frac{22x}{4} + \frac{8x}{4} = 75 \\ = \frac{30x}{4} = 75 \\ 30x = 75 \times 4 \\ 30x = 300 \\ x = \frac{300}{30} \\ x = 10$

therefore the

breadth=x=10cm

length=11/4 × x=11/4×10=27.5cm

And let's prove whether it's correct or not.

$2(27.5 + 10) = 75 \\ = 2 \times 37.5 = 75 \\ 75 = 75$

L.H.S=R.H.S

hence proved it's correct

hope it helps