Question

) The perimeter of a rectangle is 76 m and its length is two more than twice the width Find
the dimensions
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Answer 1

Step-by-step explanation:

Let the width = x

let the length = 2x+2

perimeter = 2(l+b)

76=2(2x+2+x)

76=2(3x+2)

76=6x+4

72=6x

12=x

*x=12

Answer 2

Answer:

12m,26m

Step-by-step explanation:

let the width be X

then , it's length be ,2x+2

perimeter = 2(l+b)

76=2(2x+2+x)

76=2(3x+2)

76=6x+4

-6x = 4-76

-6x = -72

x= 72/6

x= 12m

so, length = 2x+2

2(12)+2

= 26m

width = x= 12m