Question

the perimeter of a rectangle is 80 amd its length is one meter more than twice the breadth. what are it's length and breadth​

Answer 1

Answer:

Perimeter of rectangle = 80 cm

Breadth = x

Length = 2X +1

Perimeter of rectangle = 2 {l + b }

80 = 2( 2X+ 1 + x)

80. = 2( 3X+1 )

80/2 = 3X + 1

40 - 1 = 3X

39 = 3X

39/3 = X

X = 13cm = Breadth

Length = 13 x 2 + 1

= 26 + 1

= 27 cm

Answer 2

$Let \: breadth = b \: m$

$Length (l) = (2b + 1 )\: m$

$Perimeter (P) = 80 \: m$

$\implies 2(l+b) = 80$

$\implies 2( 2b + 1 + b ) = 80$

$\implies 3b + 1 = \frac{80}{2}$

$\implies 3b = 40 - 1$

$\implies 3b = 39$

$\implies b = \frac{39}{3}$

$\implies b = 13$

Therefore.,

$\red{ Breadth (b) } \green { = 13 \:m }$

$\green{ Length (l) } = 2b+1$

$= 2\times 13 + 1$

$= 26 + 1$

$\green {= 27 \: m}$

•••♪