Question

The perimeter of a rectangle is 80 m. The length of the rectangle is 7 more than
its width. Find the length and width of the rectangle.​

Answer 1

Answer :-

Given :-

• Perimeter of rectangle = 80 m
• Length = Width + 7 m

To Find :-

• Length
• Width

Solution :-

We know that,

Perimeter = 2 ( Length + Width )

Let the Width be x

Length = x + 7

Substituting the value :-

→ 80 = 2 ( x + x + 7 )

→ 80 = 2 ( 2x + 7 )

→ 80 = 4x + 14

→ 4x = 80 - 14

→ 4x = 66

→ x = 66 / 4

→ x = 16.5

• Width = 16.5 m
• Length = 23.5 m

Answer 2

According to the question,

• Width = x
• Length = x + 7

We know that,

$\begin{gathered}\qquad \longmapsto \frak{{\red{ perimeter = 2 ( length + width )}} }\\ \\→ 80 = 2 ( x + x + 7 ) \\ \\ → 80 = 2 ( 2x + 7 ) \\ \\ → 80 = 4x + 14 \\ \\ → 4x = 80 - 14 \\ \\ → 4x = 66 \\ \\ → x = 66 / 4 \\ \\ → x = 16.5 \\\end{gathered}$

$[/tex]</p><p></p><ul><li><strong><u>Width = 16.5 m</u></strong></li><li><strong><u>Length = 23.5 m</u></strong></li></ul><p>[tex]\: \: \: \: \: \: \: \: \: \: \huge \bold{@WildCat7083 }$