Question

the perimeter of a rectangle is 900 meter. if its length is 50 more than its breadth, find its area​

Answer 1

Answer:50,000msquare

Step-by-step explanation:

Perimeter=900,let’s take breadth be x.so,length will be 50 + x.900=2[(x+50)+x].therefore x=200.so,breadth will be 200 and length will be 250.so,area of rectangle is 200*250.so,area of given rectangle is 50000

Answer 2

Given ,

Perimeter of rectangle = 900 m

Length of rectangle = 50 + breadth

Let ,

Breadth of a rectangle be x

We know that the perimeter of rectangle is given by :

$\pink{ \sf\large \fbox{ \fbox{Perimeter = 2(L + B)}} }$

Substitute the values , we obtain

$\sf \implies900 = 2(50 + x + x) \\ \\\sf \implies 450 = 50 + 2x \\ \\\sf \implies 400 = 2x \\ \\\sf \implies x = 200$

Thus , breadth = 200 m and length = 250 m

Now , the area of rectangle is given by

$\pink{ \sf\large \fbox{ \fbox{Area = Length × Breadth }} }$

Substitute the values , we get

$\sf \implies Area = 250 \times 200 \\ \\ \sf \implies Area = 50000 \: \: {m}^{2}$

Hence , the area of rectangle is 50000 m²