Question

: The perimeter of a rectangle is 90m. If its length exceeds its breadth by 2m, find its area​

Answer 1

Step-by-step explanation:

Let breadth of rectangle be x.

Then, its length = x+5

Now, Perimeter = 90 m

2(x+x+5)=90

2x+5=45

2x=40

x=20 m

Therefore, length = 25 m and breadth = 20

YOU CAN TAKE PREFERENCE FROM THIS

Answer 2

Given

• Perimeter of a rectangle is 90m.
• It's length exceeds it's breadth by 2m.

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To find

• Area of the rectangle.

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Solution

• Let the breadth of the rectangle be b meters, then it's length will be (b + 2)m.

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→ Perimeter = 90

→ 2(l + b) = 90

→ 2(b + 2 + b) = 90

→ 2b + 2 = 90/2

→ 2b + 2 = 45

→ 2b = 45 - 2

→ 2b = 43

→ b = 43/2

→ b = 21.5 m

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• Then, length = 23.5 m

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★ Area = length × breadth

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→ Area = 23.5 × 21.5

→ Area = 505.25 m²

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Hence,

• Area of the rectangle is 505.25m².

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⠀⠀ ⠀⠀⠀ ☆ Some Formulae ☆

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→ Area of square = (side)²

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→ Area of rectangle = length × breadth

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→ Area of triangle = ½ × base × height

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→ Area of parallelogram = base × height

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→ Area of Circle = πr²