Question

The perimeter of a rectangle is 90m whose breadth is 10 m less than its length . Find the breadth

Answer 1

Answer:

2(l+b)=perimeter

b=l-10

90=2(l+l-10)

90=2(2l-10)

45=2l-10

l=55/2

b=(55/2)-10

b=35/2

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

perimeter of the rectangle is 90m

let the breadth be x and length be y

x= y-10

perimeter of a rectangle =2(l+b)

90=2(y+y-10)

90=2y+2y-20

90=4y-20

4y =90+20

4y=110

y=110/4

y=27.5

x=y-10

x=27.5-10

x=17.5

therefore , breadth of the rectangle is 17.5 m