Question

The perimeter of a rectangle is a+2ab +c, one of its side is a-5ab, Find the other side.

Answer 1

Answer:

Step-by-step explanation:

Draw the rectangle.  Label the short sides 'a = 4' and the long sides 'b'.  Label the interior (area) 'C'.

The perimeter is 2a + 2b

And area = a times b

If the perimeter = twice the area 'C', the n the equation will look like this:

2a + 2b = 2C

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Now to solve for side b (length 'L'):

We know that a = 4.  

2a + 2b = 2C and

ab = C =  4b = C We need to redefine b in terms of C:

b = C/4 Plug it back into the original:

2a + 2b = 2C

2(4) + 2(C/4) = 2C  Expand:

8+C/2 = 2C Multiply through by 2

16 + C = 4C Subtract C

16 = 3C  Divide by 3

16/3 = C  Now plug C into the original

ab = C

4b = 16/3 Divide by 4

b = 4/3 the length of side b = 4/3