Question

The perimeter of a rectangle is given by 14a³-28a²+38. If one of its sides is 7a³+2a²-4, find the other side.....​

Answer 1

Answer:

OTHER SIDE= -16a²+23

Step-by-step explanation:

perimeter of rectangle =2(l+b)

14a³-28a²+38=2(7a³+2a²-4+b)

14a³-28a²+38=14a³+4a²-8+2b

-4a² - 28a² +38+8=2b

-32a²+46=2b

b= -16a²+23