Question

The perimeter of a rectangle is given by 14a³-28a²+38. If one of its sides is 7a³+2a²-4, find the other side​

Answer 1

Answer:

b=-16a²+13

Step-by-step explanation:

we know that perimeter of a rectangle is

2(l+b)

given 2(7a³+2a²-4+b)=14a³-28a²+38

(b is the other side)

7a³+2a²-4+b=7a³-14a²+19

2a²-13+b=-14a²

b=-16a²+13