The perimeter of a rectangle is numerically equal to its area .If the width of a rectangle is 11 upon 4 cm. than its length is solve
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Given perimeter of rectangle = Area of rectangle and width = 11/4
2(L+W) = L*W
2(L + 11/4) = 11L/4
2L + 11/2 = 11L/4
11L/4 - 2L = 11/2
3L/4 = 11/2
6L = 44
L = 44/6
L = 22/3.
I hope this helps you understand. Please let us know if there is any confusion.
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