The perimeter of a rectangle is numerically equal to its area. If the width of the rectangle is 11÷4cm than its length is
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a+b = a*b (where a is the length and b is the breadth)
a+11/4 = 11a/4
4a+11 = 11a
11 = 7a
a = 11/7
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a+11/4 = 11a/4
4a+11 = 11a
11 = 7a
a = 11/7
If it helps you then please mark it as brainliest
Answered by
1
Given perimeter of rectangle = Area of rectangle and width = 11/4
2(L+W) = L*W
2(L + 11/4) = 11L/4
2L + 11/2 = 11L/4
11L/4 - 2L = 11/2
3L/4 = 11/2
6L = 44
L = 44/6
L = 22/3.
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