the perimeter of a rectangle is numerically equal to its area.if the width is 17/3 then what is the length
Answers
Answered by
0
Let Length be x cm.
Breadth = 17/3 cm
Area = 17/3×x
=17x/3 sq m
Perimeter = 2(L+B)
=2(17/3+x)
34/3+2x
Then,
34/3+2x=17x/3
x=34/11 m
Breadth = 17/3 cm
Area = 17/3×x
=17x/3 sq m
Perimeter = 2(L+B)
=2(17/3+x)
34/3+2x
Then,
34/3+2x=17x/3
x=34/11 m
Answered by
5
let the length of rectangle be 'L cm ' and width be ' B cm '
according to question ,
perimeter of rectangle = its area
2( L + B ) =L × B
given , if the width (B) = 17/ 3 then , L =?
2 ( L + 17 / 3 )= L × 17 / 3
2( 3L + 17 ) / 3 = 17 L / 3
2( 3L + 17 ) =3 × 17L / 3
6L + 34 = 17 L
17L - 6L = 34
11L = 34
L = 34 / 11 cm
therefore , length = 34 /11 cm
_______________________________
Your Answer : 34 /11 cm
_______________________________
according to question ,
perimeter of rectangle = its area
2( L + B ) =L × B
given , if the width (B) = 17/ 3 then , L =?
2 ( L + 17 / 3 )= L × 17 / 3
2( 3L + 17 ) / 3 = 17 L / 3
2( 3L + 17 ) =3 × 17L / 3
6L + 34 = 17 L
17L - 6L = 34
11L = 34
L = 34 / 11 cm
therefore , length = 34 /11 cm
_______________________________
Your Answer : 34 /11 cm
_______________________________
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