Question

The perimeter of a rectangle is
$28 {x}^{3} + 16 {x}^{2 } + 8x + 4$
One of its sides is
$8 {x}^{2} + 4x$
Find the other side

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Answer 1

Answer:

Perimeter of a rectangle (2l + 2b)

= 28x3 + 16x2 + 8x + 4

Let one side (l) = 8x2 + 4x

∴ 2l = 2(8x2 + 4x) = 16x2 + 8x

∴ 2b = (28x3 = 16x2 + 8x + 4) – (16x2 + 8x)

= 28x3 + 16x2 + 8x + 4 – 16x2 – 8x

= 28x3 + 4

∴ Other side (b) = (28x3 + 4)/2

= 14x3 + 2

Answer 2

Answer:

PERIMETER OF RECTANGLE = 2I+2b

2I+ 2b = 28x³+16x²+8x+4

let one side is 2l

2l = 2(8x²+4x)

16x²+ 8x + 2b = 28x³+16x²+8x+4

2b = (28x³+ 16x²+8x+4) - (16x²+8x)

2b = 28x³+ 4

second side is 28x3+4/2 because

2b = 28x³+4

b = 28x³+4

2

second side is 14x³+2

ANSWER = 14X²+2

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