Question

The perimeter of a rectangle of an an area 650cm² , whose breadth is 13 cm , then find the length​

Answer 1

$\huge\mathfrak\blue{Answer:}$

Given:

• We have been given that the area of a rectangle is 650cm².
• The breadth of rectangle is 13cm.

To Find:

• We need to find the perimeter and length of rectangle.

Solution:

We know that perimeter of rectangle is 2(l + b) and area of rectangle is l × b.

We have been given that the area if rectangle is 650cm² and breadth is 13cm.

Therefore length × bredth = Area

=> Length = Area/Breadth

=> Length = 650/13

=> Length = 50cm

Now, if we need to calculate the perimeter of rectangle, we have

Perimeter = 2(l + b)

=> Perimeter = 2(50 + 13)

=> Perimeter = 2(63)

=> Perimeter = 126cm²

Hence, the length of rectangle is 50cm and its perimeter is 126cm².

Answer 2

$\huge\mathfrak\orange{Answer:-}$

Given:-

Area of a rectangle:- 650cm²

Breadth of the rectangle:- 13cm

To Find:-

Length and Perimeter of the rectangle.

Solution:-

$\longrigharrow\tt{Area\:of\:a\: rectangle=Length ×Breadth}$

$\longrightarrow\tt{650cm^2=L{\times}13cm}$

$\longrightarrow\tt{L={\dfrac{\cancel{650}}{\cancel{13}}}}$

$\longrightarrow\tt{L=50cm}$

$\longrightarrow\tt{Length=50cm}$

$\longrightarrow\tt{Perimeter \:of \: rectangle=2(l+b)}$

$\longrightarrow\tt{Perimeter\:of\: rectangle=2(13+50)}$

$\longrightarrow\tt{Perimeter\:of\: rectangle=2(63)}$

$\longrightarrow\tt{Perimeter\:of \: rectangle= 126cm^2}$

$\sf{Hence,\:the\; perimeter\:and\;the\;length\:of\:the}$

$\sf{rectangle \:is\:650cm^2 \: and\:50cm\: respectively.}$

Hope it helps!