Question

the perimeter of a rectangle paper of breadth 23/2 cm is 30 cm. find the length of the paper ?​

Answer 1

Answer:

perimeter of rectangle = 2( l + b )

30 = 2( l + 23/2)

30 = (2 l+23)

30 - 23 = 2 l

l = 7/2 cm  Ans

Area of rectangle= l * b

7/2*23/2

= 161/4 cm 2 Ans

Answer 2

Step-by-step explanation:

Perimeter of rectangle = 2 (L+B)

30 = 2(L+23/2)

$30 = 2(l + \frac{23}{2}) \\ 30 = 2( \frac{2l + 23}{2}) \\ 30 = \frac{2l}{2} \times 2 + \frac{23}{2} \times 2 \\ 30 = 2l + 23 \\ 2l = 30 - 23 \\ 2l = 7 \\ l = \frac{7}{2} \\ l = 3.5cm$