the perimeter of a rectangle PQRS is 70 cm of PQ:QR = 3:4 THEN FIND OR
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Let the sides of the rectangle be 3x >= 4x respectievely (As given 3:4)
Then ;
Perimeter of Rectangle = 2(1l + b) so; 2(3x + 4x) = 70 2(7x) = 70 7x = 70/2
= 35
then x = 35/7 theirfore x = 5
then side QR (As it is taken as the breadth)
=;
4x = 5x4 20
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