the perimeter of a rectangle swimming pool is 15 M its length is 2 metre more than twice its breadth what are the length and the and the breadth of the pool
Answers
Answered by
1
2 ( l+b) =15
l =2+b
2( 2+b +b) 15
2(2+2b)=15
4+4b=15
4b =15-4=11
b =11/4
l = 11/4 +2
= 19/4
l =2+b
2( 2+b +b) 15
2(2+2b)=15
4+4b=15
4b =15-4=11
b =11/4
l = 11/4 +2
= 19/4
Answered by
0
Perimeter of a rectangle is given by
2(length+breadth) so A/Q
2( l+b) =15
And it is given that
l =2+2b
So after substituting we get
2( 2+2b +b) 15
2(2+3b)=15
4+6b=15
6b =15-4=11
b =11/6
By substituting the value we get
l = 2(11/6) +2
= 17/3
So
Length = 17/3
Breadth = 11/6
2(length+breadth) so A/Q
2( l+b) =15
And it is given that
l =2+2b
So after substituting we get
2( 2+2b +b) 15
2(2+3b)=15
4+6b=15
6b =15-4=11
b =11/6
By substituting the value we get
l = 2(11/6) +2
= 17/3
So
Length = 17/3
Breadth = 11/6
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