Question

The perimeter of a Rectangle with dimensions (2x + 10) and (x + 20) is 240 cm find its dimensions. ​

Answer 1

Answer:

perimeter=2(l+b)=2(2x+10+x+20)=240

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Length of the Rectangle is 70 cm and Breadth is 50 cm.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Dimensions of the Rectangle = (2x + 10) and (x + 20)

Perimeter of the Rectangle = 240 cm

To Find :

Its dimensions

Solution :

★ Perimeter = $\boxed{\sf{2(Length+Breadth)}}$

$\sf{\longrightarrow} \: 2[(2x + 10) + (x + 20)] = 240$

$\sf{\longrightarrow} \: 4x + 20+ 2x + 40= 240$

$\sf{\longrightarrow} \: 6x + 60 = 240$

$\sf{\longrightarrow} \: 6x = 240 - 60$

$\sf{\longrightarrow} \: 6x = 180$

$\sf{\longrightarrow} \: x = \dfrac{180}{6}$

$\sf{\longrightarrow} \: x = 30$

$\rule{300}{1.5}$

★ Value of (2x + 10)

$\sf{\longrightarrow} \: 2(30) + 10$

$\sf{\longrightarrow} \: 60 + 10$

$\sf{\longrightarrow} \: 70$

Length is 70 cm

$\rule{300}{1.5}$

★ Value of (x + 20)

$\sf{\longrightarrow} \: 30 + 20$

$\sf{\longrightarrow} \: 50$

Breadth is 50 cm

$\therefore$ The Length of the Rectangle is 70 cm and Breadth is 50 cm.