Question

the perimeter of a rectangular board is 58 m. The length of the board is 10 m. Find out the width of the board? explanation

Answer 1

Question:

The perimeter of a rectangular board is 58 m. The length of the board is 10 m. Find out the width of the board?

Given:

• Perimeter of the board

• Length of the board

To Find:

• The width of the board

Formula Used:

$P=2(l+b)\\\textsf{Where l is length and b is breadth or width}$

Solution:

Perimeter of the board = 58 m

Length of the board = 10 m

Perimeter =

$P=2(l+b)\\\textsf{Where l is length and b is breadth or width}$

$58=2(10+b)\\\\\\58=(2\times10)+ 2b\\\\\\58=20+2b\\\\\\58-20=2b\\\\\\2b=58-20\\\\\\2b=38\\\\\\b=\frac{38}{2}\\\\\\b=19cm$

Answer:

• Width of the rectangle is 19 cm

Answer 2

$\huge\bold{Answer:-}$

Given:-

• The perimeter of the rectangular field is 58m
• The length of the board is 10m .

To Find:-

• The width of the rectangular board.

Solution:-

we know,

The perimeter of a rectangle = 2 × ( length + breadth ) square units.

so,

Here , The length is given = 10m

The perimeter of the rectangular board is = 58 m

let, the width of the board be x m.

Therefore ,

➱ Perimeter = 2 ( l + b )

➱ 58 = 2 ( 10 + x )

➱ $\dfrac{58}{2}$ = 10 + x

➱ 29 = 10 + x

➱ x = 29 - 10

➱ x = 19 m

Therefore , the width of the rectangular board is 19 m