Question

The perimeter of a rectangular Field is 100m if the length is 35m find its breadth also find its area

Answer 1

Answer:

The breadth of the rectangular field is 15m

The area of the rectangular field is 525

Answer 2

$\huge \underbrace { \underline{\frak{Answer}}}$

$\underline{\underline{ \large{ \frak{ \color{red}{Given::}}}}}$

$\mapsto \sf{Perimeter \: of \: rectangle=100m}$

$\mapsto \sf{Length \: of \: rectangle=35m}$

$\underline{\underline{ \large{ \frak{ \color{blue}{To \: find::}}}}}$

$\leadsto \sf{ Breadth \: of \: rectangle.}$

$\leadsto \sf{ Area\: of \: rectangle.}$

$\underline{\underline{ \large{ \frak{ \color{indigo}{Formula \: required::}}}}}$

$\pink{ \star}{ \fbox{Perimeter of rectangle=2(length + breadth)}} \pink{ \star}$

$\pink{ \star}{ \boxed {\rm{ Area \: of \: rectangle=length \times breadth}}} \pink{ \star}$

$\underline{\underline{ \large{ \frak{ \color{cyan}{According \: to \: Question::}}}}}$

${ : :\implies \sf{Perimeter \: of \: rectangle=2(length + breadth)}}$

${ : :\implies \sf{100m=2(35m + breadth)}}$

${ : :\implies \sf{ \frac{100}{2}m = 35m + breadth}}$

${ : :\implies \sf{ 50m = 35m + breadth}}$

${ : :\implies \sf{ Breadth \: of \: rectangle = 50m - 35m}}$

${ : :\implies \sf{ Breadth \: of \: rectangle =15m}}$

${ ::\implies{\sf{ Area \: of \: rectangle=length \times breadth}}}$

${ ::\implies{\sf{ Area \: of \: rectangle=50m \times 15m}}}$

${ ::\implies{\sf{ Area \: of \: rectangle=750 {m}^{2} }}}$

$\underline{\underline{ \large{ \frak{ \color{lime}{Hence, }}}}}$

$\: \: \: \: \: \: \: \: \: \: \pink{ \star} \underline{ \fbox{Breadth of rectangle=15m}} \pink{ \star}$

$\: \: \: \: \: \: \: \: \: \: \pink{ \star} \underline { \boxed{ \rm{Area \: of \: rectangle = 750 {m}^{2} }} }\pink{ \star}$

$\underline{\underline{ \large{ \frak{ \color{green}{Know \: more \: about \: rectangle::}}}}}$

$\begin{array}{ |c|c| } \hline \sf Perimeter \: of \: rectangle& \sf 2(length + breadth) \\ \hline \sf Area \: of \: rectangle& \sf length \times breadth\\ \hline \sf Length \: of \: rectangle& \sf\frac{Area }{ Breadth} \\ \hline \sf Breadth \: of \: rectangle& \sf \frac{Area}{Length} \\ \hline \sf Diagonal \: of \: rectangle& \sf \sqrt{ {length}^{2} + {breadth}^{2} } \\ \end{array}$