Question

The Perimeter of a Rectangular Field is 126 m.if the length of the field is 3 more than twice the breadth, what are the dimensions of the field ?
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Answer 1

Answer:

Answer:Perimeter of the field = 126m

Answer:Perimeter of the field = 126mLet the breadth be x

Answer:Perimeter of the field = 126mLet the breadth be xSo , the length will be 3×x = 3x

Answer:Perimeter of the field = 126mLet the breadth be xSo , the length will be 3×x = 3xPerimeter of rectangle = 2×(l+b)

Answer:Perimeter of the field = 126mLet the breadth be xSo , the length will be 3×x = 3xPerimeter of rectangle = 2×(l+b)Therefore,

Answer:Perimeter of the field = 126mLet the breadth be xSo , the length will be 3×x = 3xPerimeter of rectangle = 2×(l+b)Therefore, 2×(3x+x) = 126

Answer:Perimeter of the field = 126mLet the breadth be xSo , the length will be 3×x = 3xPerimeter of rectangle = 2×(l+b)Therefore, 2×(3x+x) = 126→ 3x+x = 126/2

Answer:Perimeter of the field = 126mLet the breadth be xSo , the length will be 3×x = 3xPerimeter of rectangle = 2×(l+b)Therefore, 2×(3x+x) = 126→ 3x+x = 126/2 → 2×(3x+x) = 126

2×(3x+x) = 126→ 3x+x = 126/2

→ 3x+x = 63

→ 3x+x = 63→ x+x = 63/3

→ x+x = 21

→ x+x = 21x and x get crisscrossed here ↑ ,So only 1 x will be in this equation .....

→ x+x = 21x and x get crisscrossed here ↑ ,So only 1 x will be in this equation .....Then, x = 21

→ x+x = 21x and x get crisscrossed here ↑ ,So only 1 x will be in this equation .....Then, x = 21x = Breadth and 3x = Length

→ x+x = 21x and x get crisscrossed here ↑ ,So only 1 x will be in this equation .....Then, x = 21x = Breadth and 3x = Lengthx = 21 = Breadth

→ x+x = 21x and x get crisscrossed here ↑ ,So only 1 x will be in this equation .....Then, x = 21x = Breadth and 3x = Lengthx = 21 = BreadthThen, 3x = 21×3 = 63 = Breadth

→ x+x = 21x and x get crisscrossed here ↑ ,So only 1 x will be in this equation .....Then, x = 21x = Breadth and 3x = Lengthx = 21 = BreadthThen, 3x = 21×3 = 63 = BreadthMark me as brainliest......