Question

The perimeter of a rectangular field is 260 feet. The length of the field is 10 feet more than twice the width of the field. What is the length of the field?

Answer 1

Answer:the length of the field is 70feet

Step-by-step explanation:let the breadth=2X

let the length=2X+10

perimeter of rectangle=2(l+b)

260=2(2X+2X+10)

260=2(4X+10)

260=8X+20

260-20=8X

240=8X

240/8=X

30=X

so the width=2X

=2*30

=60

so the length=2X+10

=2*30+10

=60+10

=70

Answer 2

Answer:

The Length of the rectangular field is 90 feet and Width is 40 feet.

Step-by-step explanation:

Given:-

Perimeter of the rectangular field = 260 feet

To find :-

The length of the field

Solution :-

Consider Width of the Rectangle as x

Consider the length of the Rectangle as 10+2x

Perimeter of Rectangle =

⇒$\tt{2(Length+Width)}$

⇒$\tt{2(10+2x+x=260)}$

⇒$\tt{20+4x+2x=260}$

⇒$\tt{20+6x=260}$

⇒$\tt{6x=260-20}$

⇒$\tt{6x=240}$

⇒$\tt{x= \dfrac{240}{6}}$

⇒$\tt{x=\dfrac{40}{1}}$

⇒$\tt{x=40}$

Width = $\tt{x}$

⇒$\tt{Width = 40 feet}$

Length = $\tt{10+2x}$

⇒$\tt{10+(40\times2)}$

⇒$\tt{10+80}$

⇒$\tt{90}$

Length = $\tt{90 feet}$

∴ The Length of the rectangular field is 90 feet and Width is 40 feet.

Verification:-

⇒$\tt{2(Length+Width)}$

⇒$\tt{2(90+40)=260}$

⇒$\tt{180+40=260}$

⇒$\tt{260 =260 }$

∴ LHS = RHS

∴ The Length of the rectangular field is 90 feet and Width is 40 feet.