Question

The perimeter of a rectangular field is 32 m. Its length is 9 m. Find the area of the field!

Answer 1

Area of the field is 63 $m^{2}$.

Step-by-step explanation:

We are given that the perimeter of a rectangular field is 32 m and length is 9 m.

Let the length of rectangular field be L = 9 m

and breadth of rectangular field be B.

As we know that the Perimeter of rectangle is given by;

   Perimeter of rectangle = 2 $\times$ (L + B)

                             32 m    =  2 $\times$ (9 + B)

                               $\frac{32}{2}$      = 9 + B

                              B = 16 m - 9 m = 7 m

Hence, the breadth of rectangular field is B = 7 m.

Now, Area of rectangular field is given by;

           Area of rectangle = Length $\times$ Breadth

                                          = 9 m $\times$ 7 m

                                          = 63 $m^{2}$.

Therefore, the area of the field is 63 $m^{2}$.