Question

The perimeter of a rectangular field is 628m.The length of the field exceeds its width by 6m.Find the dimensions.

Answer 1

Answer:

• Breadth of the rectangular field = 154 m
• Length of the rectangular field = 160 m

Step-by-step explanation:

GIVEN

• Perimeter of a rectangular field is 628 m.
• Let the breadth of the rectangular field be x m.
• Its length = (x + 6) m

FORMULA

• Perimeter of rectangle = 2(Length + Breadth) unit

BY APPLYING THE FORMULA OF PERIMETER

Perimeter of rectangle = 2(Length + Breadth) unit

→ 628 = 2(x + 6 + x)

→ 2x + 6 = 628/2

→ 2x + 6 = 314

→ 2x = 314 - 6

→ 2x = 308

→ x = 308/2

→ x = 154

∴ Its dimensions are:

Breadth of the rectangular field = x = 154 m

Length of the rectangular field = (x + 6) = (154 + 6) = 160 m

Answer 2

Answer:

Given :-

• The perimeter of a rectangular field is 628 m. The length of the field exceeds it's width by 6 m.

To Find :-

• What is the dimensions.

Formula Used :-

${\red{\boxed{\small{\bold{Perimeter\: of\: rectangle =\: 2(Length + Breadth)}}}}}$

Solution :-

Let, the breadth be x m

And, the length will be x + 6 m

Given :

• Length = x + 6 m
• Breadth = x m
• Perimeter = 628 m

According to the question by using the formula we get,

⇒ $\sf 2(x + 6 + x) =\: 628$

⇒ $\sf 2(2x + 6) = 628$

⇒ $\sf 2x + 6 =\: \dfrac{\cancel{628}}{\cancel{2}}$

⇒ $\sf 2x + 6 =\: 314$

⇒ $\sf 2x =\: 314 - 6$

⇒ $\sf 2x =\: 308$

⇒ $\sf x =\: \dfrac{\cancel{308}}{\cancel{2}}$

➠ $\sf\bold{\pink{x =\: 154\: m}}$

Hence, the required length and breadth are,

$\leadsto$ Breadth of a rectangular field :-

↛ $\sf x\: m$

➦ $\sf\bold{\purple{154\: m}}$

$\leadsto$ Length of a rectangular field :-

↛ $\sf (x + 6)\: m$

↛ $\sf (154 + 6)\: m$

➦ $\sf\bold{\purple{160\: m}}$

${\underline{\boxed{\small{\bf{\therefore The\: length\: and\: breadth\: of\: a\: rectangular\: field\: is\: 160\: m\: and\: 154\: m\: respectively\: .}}}}}$