Question

The perimeter of a rectangular field is 638m.The length of the field exceeds it's width by 6m.Find the dimensions​

Answer 1

Step-by-step explanation:

let B = X m

then L= X + 6 m

The perimeter of a rectangular field is 638m

2(L + B) = 638

L+B = 638/2

L+B = 319

X+X+6= 319

2x= 319-6

B=X = 313/2 m

X+6=313/2+6

L= 325/2 m