The perimeter of a rectangular field is 80m. If the length of the field is decreased by 2m and breadth is increased by 2m, the area is increased by 36 sq. km. Find the length and breadth of the rectangle.
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2L + 2B = 80
L + B = 40
L*B = X
(L-2)*(B+2)=X +36
LB + 2L -2B -4 = X +36
X + (80-2B) -2B -4 = X +36
76-4B= 36
B=10
L=30
L + B = 40
L*B = X
(L-2)*(B+2)=X +36
LB + 2L -2B -4 = X +36
X + (80-2B) -2B -4 = X +36
76-4B= 36
B=10
L=30
khushivk:
How L+B =40?
2L + 2B = 80. .... 2(L+B)=80..... L + B = 80/2. .... L + B = 40
Ok
Thank u so much...
Hws the 4th step??
they gave it in question length decreased by 2 and breadth increased by 2 and we considered the area is X
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