the perimeter of a rectangular field is 820 meters ans its area is 400meter square. find the breadth of the rectangle
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LET B= BREADTH AND L=LENGTH
So,
It is given that the perimeter of the rectangular field=820 m
=> 2(L+B)=820
=> 2L+2B=820.....1)
It is also given that the area of the rectangular field=400 m²
=> L×B=400.....2)
From eqn 1), the value of B=820-2L/2
Now, we have to put the value of B in eqn 2):-
=>L×B=400
=>L×(820-2L/2)=400
=>820L-2L²/2=400
=>820-2L²=400×2
=>820-2L²=800
=>-2L²=800-820
=>-2L²=-20
=>2L²=20
=>L²=20/2
=>L²=10
=>L=√10
So, L=√10
Now, putting the value of L=√10 in eqn 1):-
=>2L+2B=820
=>2×√10+2B=820
=>2√10+2B=820
=>2B=820-2√10
=>2B=813.67
=>B=813.67/2
=>B=406.835
So, LENGTH=√10 m and BREADTH=406.835 m
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